Item 2.2.4.a.
\(n+2\) terms, since to get 1 using the formula \(6n+7\) we must use \(n=-1\text{.}\) Thus we have \(n\) terms, plus two, when \(n=0\) and \(n=-1\text{.}\)
\(n+2\) terms, since to get 1 using the formula \(6n+7\) we must use \(n=-1\text{.}\) Thus we have \(n\) terms, plus two, when \(n=0\) and \(n=-1\text{.}\)