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For each case, you must use the recurrence to find \(f(1)\text{,}\) \(f(2)\) ... \(f(5)\text{.}\) But notice each time you just add three to the previous. We do this 5 times.

1. \(\displaystyle f(5) = 15\text{.}\)

2. \(\displaystyle f(5) = 16\text{.}\)

3. \(\displaystyle f(5) = 17\text{.}\)

4. \(\displaystyle f(5) = 115\text{.}\)