Returning to our example above, we have \(\card{A} = 12\text{,}\) \(\card{B} = 5\text{,}\) \(\card{C} = 8\text{.}\) We also have \(\card{A \cap B} = 2\text{,}\) \(\card{A \cap C} = 6\text{,}\) \(\card{B \cap C} = 3\text{,}\) and \(\card{A \cap B \cap C} = 1\text{.}\) Therefore: