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Now we know what to do. To prove that the converse is false we need to find two integers \(a\) and \(b\) so that \(a\) is odd or \(b\) is odd, but \(a+b\) is not odd (so even). That's easy: 1 and 3. (remember, “or” means one or the other or both). Both of these are odd, but \(1+3 = 4\) is not odd.