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Let
\(n\)
be an integer. Assume
\(n\)
is odd. So
\(n = 2k+1\)
for some integer
\(k\text{.}\)
Then
\begin{equation*} 7n = 7(2k+1) = 14k + 7 = 2(7k +3) + 1\text{.} \end{equation*}
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