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If we replace
\(x\)
by
\(3x\)
we get
\begin{equation*} \frac{1}{1-3x} = 1 + 3x + 9x^2 + 27x^3 + \cdots \mbox{ which generates } 1, 3, 9, 27, \ldots\text{.} \end{equation*}
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