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(b) Again, we can divide by 3. However, doing so blindly gives us \(8 \equiv 13 \pmod{15}\) which is no longer true. Instead, we must also divide the modulus 15 by the greatest common factor of \(3\) and \(15\text{,}\) which is \(3\text{.}\) Again we get

\begin{equation*} 8 \equiv 13 \pmod 5\text{.} \end{equation*}
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