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Now observe that if there are going to be solutions, then for those values of \(x\) and \(y\text{,}\) the two sides of the equation must have the same remainder as each other, no matter what we divide by. In particular, if we divide both sides by 17, we must get the same remainder. Thus we can safely write

\begin{equation*} 17x + 29y \equiv 41 \pmod{17}\text{.} \end{equation*}
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