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Now solve this like we have in this section. Write it as a congruence modulo 13:
\begin{equation*}
\begin{aligned}0 \amp \equiv 6 + 51k \pmod{13}\\
-12k \amp \equiv 6 \pmod{13}\\
2k \amp \equiv -1 \pmod{13}\\
2k \amp \equiv 12 \pmod{13}\\
k \amp \equiv 6 \pmod{13}.
\end{aligned}
\end{equation*}
so \(k = 6 + 13j\text{.}\) Now go back and figure out \(x\text{:}\)
\begin{equation*}
\begin{aligned}13x \amp = 6 + 51(6+13j)\\
x \amp = 24 + 51j.
\end{aligned}
\end{equation*}
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