\(32\text{,}\) which is \(26+6\text{.}\)
The sequence is arithmetic, with \(a_0 = 8\) and constant difference 6, so \(a_n = 8 + 6n\text{.}\)
\(30500\text{.}\) We want \(8 + 14 + \cdots + 602\text{.}\) Reverse and add to get 100 sums of 610, a total of 61000, which is twice the sum we are looking for.