\(A \times B = \{(1,3), (1,4), (1,5), (2,3), (2,4), (2,5)\}\text{.}\)

\(A \times A = A^2 = \{(1,1), (1,2), (2,1), (2,2)\}\text{.}\)

\(|B\times B| = 9\text{.}\) There will be 3 pairs with first coordinate \(3\text{,}\) three more with first coordinate \(4\text{,}\) and a final three with first coordinate \(5\text{.}\)